Let

$a=1\mathrm{.}02^9$

$b=-1\mathrm{.}02^9$

$c=1\mathrm{.}02^1$

$3\mathrm{.}1$ Convert these floating point numbers to binary using the simple model

described in the textbook for representing $($express the result in binary$)$ :

$14-$bits

$5$ bits for the exponent with a bias of $15$

$8$ bits for the normalized mantissa $($no hidden bit$)$

$1$ bit for the sign

$a=$

$b=$

$c=$

$3\mathrm{.}2$ Perform the following calculations using binary arithmetic:

$b+(a+c)=$

$(b+a)+c=$

$3\mathrm{.}3$ Explain why you got the result you did.

$3\mathrm{.}4.$ Would you get the same kind of result using multiplication rather then

addition $($why or why not$)?$