Question: Let $A$ and $B$ be two events from a sample space $5$, such that $operatorname (Pr}(A)=frac{1}{3}, operator name {Pr}(B)=frac{1}{2}$, and $operatorname{Pr}(A cap B)=frac{1}{8}$. Compute $operatorname{Pr}left(

Let $A$ and $B$ be two events from a sample space

Let $A$ and $B$ be two events from a sample space $5$, such that $\operatorname (Pr}(A)=\frac{1}{3}, \operator name {Pr}(B)=\frac{1}{2}$, and $\operatorname{Pr}(A \cap B)=\frac{1}{8}$. Compute $\operatorname{Pr}\left( \cup B^{C} ight)$. (For numerical answers, write your answer with three decimals and use truncation. For example, if your result is $1.3589$ write $1.358$ and if your result is $0.6866$ write $0.686 $ ) $$ SP.PC. 1380

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