Let C(x) be the cost function and R(x) the revenue function. Compute the marginal cost, marginal revenue, and the marginal profit functions. C(x)=0.0005x-0.024x + 200x + 40,000 R(x) = 400x OC'(x)=0.0015x+ 0.048x + 200 R'(x) = 400 P'(x)=0.0015x + 0.048x + 200 C'(x)=0.0015x -0.048x + 200 R'(x) = 400 P'(x) = -0.0015x + 0.048x + 200 C'(x) = 0.0015x-0.048x + 200 R'(x) = 400 P'(x)=0.0015x2 -0.048x-200 A cube 4 inches on an edge is given a protective coating 0.1 inches thick. About how much coating should a production manager order for 1000 cubes? About 4800 in.2 About 1600 in 2 About 6400 in.3 About 9600 in 3 Suppose the demand for a certain item is given by D(p) = -4p + 6p +2, where p represents the price of the item. Find D'(p), the rate of change of demand with respect to price. D'(p) = -8p +6 D'(p) = -4p+6 D'(p)=-8p+6 D'(p) = -4p+6 Let C(x) be the cost function and R(x) the revenue function. Compute the marginal cost, marginal revenue, and the marginal profit functions. C(x)=0.0001x-0.012x + 100x + 30,000 R(x) = 400x OC'(x)=0.0003x-0.024x + 100 R'(x) = 400 P'(x) = 0.0003x -0.024x - 300 C'(x)=0.0003x + 0.024x + 100 R'(x) = 400 P'(x) = 0.0003x + 0.024x + 300 OC'(x) = 0.0003x2 -0.024x + 100 R'(x) = 400 P'(x) = -0.0003x + 0.024x + 300 Find dy. y=x5x+4 O 15x-8 2-5x+4 15x+8 5x+4 15x-8 15x - 8 5x+4 dx dx dx 15x+8 dx 25x+4 Solve the problem. One hour after x milligrams of a particular drug are given to a person, the change in body temperature T (in degrees Fahrenheit) is given by T = x hundredth when necessary. where 0 x 3. Approximate the changes in body temperature produced by changing the drug dosage from 1 to 1.9 milligrams. Round to the nearest 1.67F 0.22F 1.5F 3.17F Provide an appropriate response. Let C(x) be the cost function and R(x) the revenue function. Compute the marginal cost, marginal revenue, and the marginal profit functions. C(x) = 0.0002x-0.024x + 200x + 40,000 R(x)=450x C'(x) = 0.0006x2 -0.048x + 200 R'(x) = 450 P'(x) = 0.0006x -0.048x-250 O C'(x)= 0.0006x2 -0.048x + 200 R'(x) = 450 P'(x) = -0.0006x2 + 0.048x + 250 C'(x) = 0.0006x + 0.048x + 200 R'(x) = 450 P'(x) = 0.0006x + 0.048x + 250 Solve the problem. V = r, where r is the radius, in centimeters. By approximately how much does the volume of a sphere increase when the radius is increased from 1.0 cm to 1.1 cm? (Use 3.14 for TT.) 1.3 cm 0.1 cm 1.5 cm 1.1 cm