Question: Let f : (-1, 1) - R be the function defined by 1+t f (t) = log 1 - 2t = log(1 + t) -

Let f : (-1, 1) - R be the function defined by 1+t f (t) = log 1 - 2t = log(1 + t) - log(1 - t) - 2t. Assuming knowledge of the derivative of log show that f is increasing on (-1, 1). Deduce that 1+t log 1 -t > 2t for t > 0. Prove that if r > 0 2 log 1+ 2 2x + 1 Deduce that for each positive r c+1/2 1+

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