Question: Let f be a differentiable function with f ( -3) = =2, f'(-3) = 5, f(-9) = 3, and f'(-9) = 6. Let the function

Let f be a differentiable function with f ( -3) = =2, f'(-3) = 5, f(-9) = 3, and f'(-9) = 6. Let the function g(x) = f (3x). Write the equation of the line tangent to the graph of g at the point where x = -3

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