Question: Let f be a twice - differentiable function with f ( 0 ) = 4 . The derivative of f is given by f '

Let f be a twice-differentiable function with f(0)=4. The derivative of f is given by f'(x)=sin(x2-2x+1) for -2x2.
(a) Find all values of x in the interval fufx=0f(0.25)0x0.25,f'(x)>0f''(x)0f(0.25)-2at which f has a critical point. Classify each as the location of a relative minimum, a relative maximum, or neither. Justify your answers.
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(b) Use the line tangent to the graph offatx=0to approximate f(0.25).
(c)On the interval 0x0.25,f'(x)>0 and f''(x)0.Is the approximation found in part (b)an overestimate oran underestimate for f(0.25)? Give a reason for your answer.
(D) using the MVT explain why the average rate of chnage over the interval [-2,2] cannot equal 1.25.
Let f be a twice - differentiable function with f

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