Let

$f(x)=x^2\sqrt[3]{x}-\frac{1}{x\sqrt[3]{x}}$

Using the basic Derivative Rules, $f^{\text{'}}(x)is$ found $tobe$:

$\frac{11}{5}{x}^{\frac{6}{3}}-\frac{4}{3}{x}^{-\frac{7}{3}}$

$x^{\frac{6}{5}}-x^{-\frac{7}{3}}$

$\frac{11}{5}{x}^{\frac{6}{5}}+\frac{4}{3}{x}^{-\frac{7}{3}}$

$\frac{11}{5}{x}^{\frac{6}{5}}+\frac{4}{3}{x}^{-\frac{1}{3}}$

None $of$ the above