let f$($x$)=(($x$^2-1,$ if $-2<+2$x$<+2),(-$x$+5,$ if x$>2)).$ Us the formula for f$($x$)$ to algebraically computer the smallest acceptable value for x near x$=-1$ that guarantees f$($x$)$ will be within $\mathrm{.}5$ of $0.$ Use exactly $3$ decimal places and remember to round in$.$