Question: Let f ( x ) = { x 3 2 s i n ( 1 x ) ; , ( x 0 ) 0 ;

Let f(x)={x32sin(1x);,(x0)0;,(x=0)
i. Calculate f'(0) using the definition. Hint: Use Example 2 below on the derivative of
xsin1x.
ii. Calculate f'(0) for x0. Hint: Use the product rule and the chain rule.
iii. Isf'(x) continuous atx=0? Hint: Use Example 2 below on the derivative of
xsin1x.
Example 2
Let
f(x)={xsin(1x);ifx00;ifx=0
Show that f(x)is continuous.
Ifx0,f(x) has no bad point. In fact, itis the product of two continuous functions x
and sin(1x), both of which are continuous away from 0.
At0, there is a problem due to the denominator being 0.We show that the function, as
defined, is still continuous at0, using sequential continuity: xlongrightarrow0Longrightarrowf(x)longrightarrowf(0).
In fact,
limxlongrightarrow0f(x)=limxlongrightarrow0xsin(1x)
=0sin(1x)xf(0)=0,we have
limxlongrightarrow0f(x)=0=f(0),
and so the function is continuous at0.
Let f ( x ) = { x 3 2 s i n ( 1 x ) ; , ( x 0 ) 0

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