Let f( x ) = x2 a) Find the linearization L(x) of fat a = 3 b) Use the linearization to approximate 2.92 c) Find 2.92 using a calculator. d) What is the difference between the approximation and the actual value of 2.92? O A. a) L(x) = 2x - 3, b) 2.8; c) 2.9, d) the approximation is about 0. 1 less than the actual value O B. a) L(x) =6x - 9, b) 8.41; c) 8.4, d) the approximation is about 0.01 greater than the actual value. O C. a) L(x) =6x - 9, b) 8.4, c) 8.41; d) the approximation is about 0.01 less than the actual value. O D. a) L(x) = 2x - 3, b) 2.8, c) 2.9, d) the approximation is about 0.1 greater than the actual value