Question: Let f(x) = 2x + 1 - 5e. Then the equation of the tangent line to the graph of f(I ) at the point (0,

Let f(x) = 2x + 1 - 5e". Then the equation

of the tangent line to the graph of f(I ) at the

Let f(x) = 2x + 1 - 5e". Then the equation of the tangent line to the graph of f(I ) at the point (0, -4) is given by y = mx + b for m b

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