Let f(x) = 39x The slope of the tangent line to the graph of f(x) at...

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Let f(x) = 39x² The slope of the tangent line to the graph of f(x) at the point (-6, 3) is The equation of the tangent line to the graph of f(x) at (-6,3) is y = mx + b for m= and b Hint: the slope is given by the derivative at x = -6, ie. f(-6+h)-f(-6) (-6)) h lim h 0 Let f(x) = 39x² The slope of the tangent line to the graph of f(x) at the point (-6, 3) is The equation of the tangent line to the graph of f(x) at (-6,3) is y = mx + b for m= and b Hint: the slope is given by the derivative at x = -6, ie. f(-6+h)-f(-6) (-6)) h lim h 0

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fax39x2 The derivative is fn ... View the full answer