Question: Let M = ( , Q, , q 0 , F ) be any DFA, and M 0 = ( , Q, , q 0
Let M = (, Q, , q0, F) be any DFA, and M0 = (, Q, , q0, Q \ F), quasi, M0 is the same as M except that the final states are non-final states and vice-versa.
Is the following true:
Prove it.
L(M') = L(M)
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