Question: Let us consider computer A and computer B executing a given application. CPI _ A = CPI _ B . Computer B has a higher

Let us consider computer A and computer B executing a given application.
CPI_A = CPI_B. Computer B has a higher frequency (clock rate),
ClockRate_B=2** ClockRate_A. Both computers have the same ISA,
however B has a more efficient complier that generates only 50%
instructions compared with A , for the same application.
To execute the given application, which machine is faster and by how much?
Let us consider computer A and computer B

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