Let $x(t)=t^3-4t^{2}t$

and $y(t)=t^2-6t3$

At $t=2,$

$x(2)=$

$y(2)=$

$\frac{dx}{dt}{|}_t||=2=$

$\frac{dy}{dt}{|}_t||=2=$

$$

$$

$\frac{dy}{dx}{|}_t||=2=$ tangent slope $=$

speed $(2)=$