Question: Let y(t) be a function which satisfies the differential equation y'=(t+1)(y-2)^2-t, for all t and y(0)=1. Show that y(t) <2 for all t0.

Let y(t) be a function which satisfies the differential equation y'=(t+1)(y-2)^2-t, for all t and y(0)=1. Show that y(t)<2 for all t0.

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