Liquid reaction A $-->2$B is taking place in a steady state packed bed reactor that has total available packing area $($A$)$ of $10$ m$2.$ The density $(\backslash$rho $)$ and packing surface $($a$)$ of the catalyst per volume are $1\mathrm{.}01$ g$/$cm$3$ and $420$ cm$2/$cm$3,$ respectively. The volumetric flow rates in and out are equivalent at $0\mathrm{.}5$ L$/$min$.$ With a rate law of $$r$$A$=$kCA$2($k $=0\mathrm{.}020$ L$2/($mol$*$ min$*$ g of catalyst$))$ and a feed in molar flowrate $($FAo$)$ of $4$ mol$/$min$,$ what percentage of the initial feed of chemical A exits the reactor? Hint: the mass of the catalyst in the reactor $($W$)$ is related to the packing area $($A$)$ by W $=\backslash$rho $*$A$/$a $.$ Please express the percentage that exits the reactor to one decimal place.