Loop $6$: Again, we have a coded message, this time as a Caeser cipher. A Caeser cipher is one in which all letters are replaced with the letter $2$ letters to the right. So$,$

A becomes C$,$ B becomes D$,$ etc. To help, I've provided the decoding cipher Use this cipher to decode the string. Call the decoded string decoded$\_$message and

print it to the screen.

Hint: Characters in the message that are not in the cipher are to be left as$-$is$.$ You can do this by using $.$ get $()$ instead of using $[]$ s$.$ For example:

cipher$[\text{'}?\text{'}]$ gives an error

cipher.get$(\text{'}?\text{'},\text{'}?\text{'})$ returns $?$ since $?$ was not found in cipher

cipher $=\{$

$\text{'}$A$\text{'}$: $\text{'}$C$\text{'},\text{'}$B$\text{'}$: $\text{'}$D$\text{'},\text{'}$C$\text{'}$: $\text{'}$E$\text{'},\text{'}$D$\text{'}$: $\text{'}$F$\text{'},\text{'}$E$\text{'}$: $\text{'}$G$\text{'},$

$\text{'}$F$\text{'}$: $\text{'}$H$\text{'},\text{'}$G$\text{'}$: $\text{'}$I$\text{'},\text{'}$H$\text{'}$: $\text{'}$J$\text{'},\text{'}$I$\text{'}$: $\text{'}$K$\text{'},\text{'}$J$\text{'}$: $\text{'}$L$\text{'},$

$\text{'}$K$\text{'}$: $\text{'}$M$\text{'},\text{'}$L$\text{'}$: $\text{'}$N$\text{'},\text{'}$M$\text{'}$: $\text{'}$O$\text{'},\text{'}$N$\text{'}$: $\text{'}$P$\text{'},\text{'}$O$\text{'}$: $\text{'}$Q$\text{'},$

$\text{'}$P$\text{'}$: $\text{'}$R$\text{'},\text{'}$Q$\text{'}$: $\text{'}$S$\text{'},\text{'}$R$\text{'}$: $\text{'}$T$\text{'},\text{'}$S$\text{'}$: $\text{'}$U$\text{'},\text{'}$T$\text{'}$: $\text{'}$V$\text{'},$

$\text{'}$U$\text{'}$: $\text{'}$W$\text{'},\text{'}$V$\text{'}$: $\text{'}$X$\text{'},\text{'}$W$\text{'}$: $\text{'}$Y$\text{'},\text{'}$X$\text{'}$: $\text{'}$Z$\text{'},\text{'}$Y$\text{'}$: $\text{'}$A$\text{'},$

$\text{'}$Z$\text{'}$: $\text{'}$B$\text{'}\}$

$62]$: $$

coded$\_$message $=""!"$F AL JV EXFO QLPP

ZEBZH JV KXFIP

YXYV ELT VLR CBBIFK'?

CBBIFKD DLLA XP EBII"!"

$***$Please answer in the simplest way possible. Thanks in advance!