Question: m = 976 g and The line which passes through the centers of two small masses, m2 = 188 g, is parallel to the

m = 976 g and The line which passes through the centers of two small masses, m2 = 188 g, is parallel to the xaxis. Initially mass m2 is at rest, and mass m is directed towards it with the velocity V1.0 (2.69 m/s), as shown. = mi 1.0 m2 k After colliding elastically, masses mi and m2 are both moving parallel to the xaxis with velocities V1, = vi, i and v2 = v2, , respectively, as shown in the second drawing. The proportionate lengths of the vectors may differ from what is shown. mi 1.f m2 "k V2.f t (a) What is the x component, in meters per second, of the final velocity of mass m ? t (b) What is the x component, in meters per second, of the final velocity of mass m?
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To solve for the xcomponent of the final velocity of both masses m1 and m2 we can use the conservation of momentum and the fact that the collision is elastic For an elastic collision both the momentum ... View full answer
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