Question: M , a solid cylinder ( M = 1 . 8 3 kg , R = 0 . 1 2 5 m ) pivots on

M, a solid cylinder (M=1.83 kg, R=0.125 m) pivots on a thin, fixed, frictionless bearing. A string wrapped around the cylinder pulls downward with a force F which equals the weight of a 0.630 kg mass, i.e., F =6.180 N. Calculate the angular acceleration of the cylinder. Tries 0/12 If instead of the force F an actual mass m =0.630 kg is hung from the string, find the angular acceleration of the cylinder. Tries 0/12 How far does m travel downward between 0.410 s and 0.610 s after the motion begins? Tries 0/12 The cylinder is changed to one with the same mass and radius, but a different moment of inertia. Starting from rest, the mass now moves a distance 0.299 m in a time of 0.450 s. Find Icm of the new cylinder.

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