Question: M + H x + M e , x + H T + M e Where, M = mesitylene, x - m - xylene, T

M+Hx+Me,x+HT+Me
Where, M= mesitylene, x-m-xylene, T= toluene, Me= methane, H= hydrogen
Mole balance on gives the following:
-dCHd=k1CH12CM+k2CxCH12
-dCMd=k1CMCH12
-dCxd=-k1CMCH12+k2CxCH12
CH(0)=0.021
CM(0)=0.0105
Where,
Cx(0)=0
k1=55.2
k2=30.2
(a) Solve the given three 0.,v0=476
NIN MAT =0 to =0.5.
line, respectively. Determine
FH=v0CH,FM=v0CM,Fx=v0Cx,FMe=f0 rates of enecies from concentrations as follows:
FT=v0(0.0105-CM-Cx)
FMe=v0(0.021-?2)
 M+Hx+Me,x+HT+Me Where, M= mesitylene, x-m-xylene, T= toluene, Me= methane, H= hydrogen

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