Question: Make a loop that creates a list where each item is a power of 2 ( i . e . 2 * * 0 ,

Make a loop that creates a list where each item is a power of 2(i.e.2**0,2**1,2**2,...,2**n) for n=0,1,2,...,999. Now do the same for a dictionary, using the corresponding exponent for each key. Using Python code

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