Question: Math question- differential calc (slope) The point P(1,2) is on the graph of y = 0.2x3 - 1.8x2 + 3.6x . Let Q be the

Math question- differential calc (slope)

The point P(1,2) is on the graph of y = 0.2x3 - 1.8x2 + 3.6x . Let Q be the point with the coordinates (x, 0.2x3 - 1.8 x2 + 3.6x ) (a) Find a formula for the slope of the secant line PQ in terms of x . (b) Find the slope of the secant line PQ (to 3 decimal places) for the given values of x. x 0.9 0.99 1.01 Slope of secant 1.1 line (c) What number would you use as an estimate for the slope of the tangent line at P(1,2)? Paper Mate

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