MATLAB Coding question ahead!

Part 1 asked:

Which was answered:

tau=20/60;%converted to hours N0=1; N=zeros(1,24);%24 columns for 24 hours of a day for i=1:24 N(i)=N0*2^(i/tau); end plot(1:24,N) grid on xlabel('Time(hours)') ylabel('Number of bacteria') Bacteria_at_the_end_of_day_1=N(24)

For this, please modify the MATLAB code above to plot the expected growth curve using the simple exponential growth model and the logistic euation (shown in 2nd image) and include MATLAB code in response. Thank you!

Recall that the simplest expression for population makes use of a doubling time, T: N(t) = N02? or E. coli bacteria, the doubling time under ideal conditions 1s about 20 minutes. Assume that you begin with a single bacterium, and grow it under optimal conditions for 1 day. Make a plot showing the number of bacteria present each hour. To do this, you will want to set up an array of 24 points, and use the above expression to fill in each value then plot the results. How many bacteria are present at the end of one day? One bacterium Recall that the simplest expression for population makes use of a doubling time, T: N(t) = N02? or E. coli bacteria, the doubling time under ideal conditions 1s about 20 minutes. Assume that you begin with a single bacterium, and grow it under optimal conditions for 1 day. Make a plot showing the number of bacteria present each hour. To do this, you will want to set up an array of 24 points, and use the above expression to fill in each value then plot the results. How many bacteria are present at the end of one day? One bacterium