May someone please help me with my calculus problems on finding Absolute extrema as well as trying to find the x value that satisfies the mean value theorem for a function, i'be tried multiple time but always get the answer wrong.

Watch help video The function f is defined by f (x) - x2 + 5 cos (2x + 2) . Find all values of x that satisfy the conclusion of the Mean Value Theorem on the interval -0.5, 4] . You may use a calculator and round to the nearest thousandth.The derivative of the function f is defined by f' (x) = (x2 + 4) sin (2x - 4) . If f(3) = -9, what is the absolute minimum value of the function f on the closed interval [0, 5]? You may use a calculator and round your answer to the nearest thousandth