Question: mean, mu=0.9050 standard deviation, s = 0.01 Sample size, n =48 Confidence interval xz(n) 0.9051.96(480.01) 0.905pm 0.002829 Lower bound = 0.905 - 0.002829 = 0.902171

mean, \mu=0.9050

standard deviation, s = 0.01

Sample size, n =48

Confidence interval

xz(n)

0.9051.96(480.01)

0.905\pm 0.002829

Lower bound = 0.905 - 0.002829 = 0.902171

Upper bound = 0.905 + 0.002829 = 0.907829

Interval from 0.9022 to 0.9078

Where did they get the 1.96 from?

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