Question: Memory operations currently take 3 0 % of execution time of program A . A new widget called a cache speeds up 8 0 %

Memory operations currently take 30% of execution time of program A. A new widget called a "cache" speeds up 80% of memory operations by a factor of 4. What is the total speed up?
Please use and explain this equation my professor gave me:
speed up =1/(1-fraction enhanced)+(fraction enhanced/speed up enhanced)

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