metal $A$ is $E_A=15M=-2500lb-$in$.$

for metal $B$ is $E_B=900.$ The bending moment acting about the $z-$axis is

$($b$)$ Determing the transformed$-$section method, draw the transformed cross section of the beam.

$($c$)$ Calculate the location of the neutral axis and the inertia of the transformed section.

$($d$)$ Calculate the maximum stress in metal $A.$

$($e$)$ Draw the maximum stress in metal $B.$

$n=E_4$ : the normal stress distribution along the $y-$axis.

d$)U_{}=-\frac{M_y}{\text{I}}$

$M$:$-2500$

b$)$