A contractor has asked you to solve the interior angle from the Beginning of Curve to STA $5+30.$ You revied the plans and know the PI is at STA $4+82$ with a deflection angle of $12{18}^{\text{'}}{00}^{\text{'}\text{'}},$ the curve has radius of $3,000Ft,$ and the beginning of curve is at $1+58\mathrm{.}74.$

$3{32}^{\text{'}}24$

$1^{5}46*00$

$12{18}^{\text{'}}00$

$5{18}^{\text{'}}{50}^{\text{'}\text{'}}$

$1812{00}^{\text{'}\text{'}}$