MISSED THIS? Read Section $11\mathrm{.}5.$ You can click on the Review link to access the section in your eText.

The vapor pressure of a substance is measured over a range of temperatures. A plot of the natural log of the vapor pressure versus the inverse of the temperature $($in Kelvin$)$ produces a

straight line with a slope of $-3\mathrm{.}47{10}^{3}K.$

Part A

What is the enthalpy of vaporization of the substance?

$2\mathrm{.}40{10}^{23}k\frac{J}{m}ol$

$285k\frac{J}{m}ol$

$28\mathrm{.}8k\frac{J}{m}ol$

$0\mathrm{.}417k\frac{J}{m}ol$