Missing the test statistic, p-value and confidence interval Also, is the answer I put correct?

Listed below are the numbers of words spoken in a day by each member of eight different randomly selected couples. Complete parts (a) and (b) below. Male 15,286 25,766 1457 7570 19 232 15,467 13,803 25,940 Female 24,665 13,620 17,951 17 417 12,690 16,679 15,871 18,476 a. Use a 0.05 significance level to test the claim that among couples, males speak fewer words in a day than females. In this example, u. is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the words spoken by the male minus words spoken by the female. What are the null and test? Ho: Ha - 0 word(s) H, : Ha - 0 word(s) Type integers or decimals. Do not round.) Identify the test statistic . t= (Round to two decimal places as needed.) Identify the P-value. P-value - (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? Since the P-value is greater than the significance level, fail to reject the null hypothesis. There | is not sufficient evidence to support the claim that males speak fewer words in a day than females. b. Construct the confidence interval that could be used for the hypothesis test described in part (a). What feature of the confidence interval leads to the same conclusion reached in part (a)? The confidence interval is |word(s)