Mixing 0.5 mol of component 1 with 0.8 mol of component 2 at a constant temperature of 25C yields a solution with a volume of 104.81 cm³. adding an additional 0.2 mol of component 2 causes the volume to increase by 17.84 cm³. adding yet another additional 0.2 mol of component 2 causes the volume to increase by an additional 17.76 cm³. given that at 25c, v_1=62.5 cm³/mol and v_2=88.7cm³/mol

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The problem involves the mixing of two components and it seems like the behavior of the solution is ... View the full answer