Question: Modify the algorithm so that, with each iteration, the algorithm reduces the number of elements by 2 elements, provided there are more than 2 elements
Modify the algorithm so that, with each iteration, the algorithm reduces the number of elements by 2 elements, provided there are more than 2 elements in the array. To compute the complexity of your algorithm, find the recurrence relationship for the algorithm (using worst case scenario) and solve it using forward or backward substitution.
Algorithm LinearRecSum( A, i, n ):
Input: An array A, an int i (starting index for the array) and n (# of elements)
Output: The sum of the n integers in A starting at index i
if n = 1 then
return A [ i ]
else
return A[i]+ LinearRecSum( A, i+1, n-1 )
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To address the given problem we want to modify the existing LinearRecSum algorithm such that with each iteration or recursive call the algorithm reduc... View full answer
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