Truth table in C programming

Please follow the instructions below and include comments and snipshot for explanation thanks.

1) Copy the C program below. This program generates the truth table for a three input OR function.

2) Modify the program to print a truth table for function f given by its canonical SOP form of f=x'y'z' + x'yz' + x'yz' + x'yz + xy'z' + xyz

Compare the printout produced by your program to the truth table below.

3) Look at the code, line 15. Notice that each logic calculation uses bitwise operators (~, &, and |), and that the last operation uses &1 to mask out all but the least significant bit. Edit the code and remove the &1 operation from your answer to part 1, then recompile and re-execute the code.

3) In fewer than 20 words, explain why the function f values appear as negative values in the resulting output.

For every execution please please take a snipshot of the output code. Thanks.

 

Transcribed Image Text:

1 #include <stdio.h> 2 PH 3 4 5 6 7 8 9 10 11 12 13 STU 14 15 2222 16 567 17 500 19 20 21 int main() { int x, y, z, f; printf("\nTruth Table\n"); printf ("x y z f\n"); } for (x { } = 0; x <= 1; x=x+1) for (y = { x, y, z, f); } } for (z = 0; z <= 1; z=z+1) { 0; y <= 1; y=y+1) return 0; f = (x | y | z) &1; printf("%d %d %d %d\n", 1 #include <stdio.h> 2 PH 3 4 5 6 7 8 9 10 11 12 13 STU 14 15 2222 16 567 17 500 19 20 21 int main() { int x, y, z, f; printf("\nTruth Table\n"); printf ("x y z f\n"); } for (x { } = 0; x <= 1; x=x+1) for (y = { x, y, z, f); } } for (z = 0; z <= 1; z=z+1) { 0; y <= 1; y=y+1) return 0; f = (x | y | z) &1; printf("%d %d %d %d\n",

Answer rating: 100% (QA)

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