Modify this code:

#include

using namespace std;

int main$()$

$\{$

const int size $=5$;

int array$1[$size$]$;

double avg;

double sum $=0\mathrm{.}0$;

cout$<<$ "Please enter $5$ values: $"<>$ array$1[$i$]$;

sum $=$ sum $+$ array$1[$i$]$;

$\}$

avg $=$ sum $/$ size;

cout $<<$ "You entered: $"$;

int max $=$ array$1[0]$;

for$($int i $=0$ ; i$<$ size ; i$++)\{$

cout$<<$ array$1[$i$]<<""$;

if$($max $<$ array$1[$i$])\{$

max $=$ array$1[$i$]$;

$\}$

$\}$

cout$<<"$ And the maximum number entered is : $"<<$ max$<<$ endl;

cout$<<$ "The summation of the entered values is: $"<<$ sum$<<$ endl;

cout$<<$ "The average of the entered values is: $"<<$ avg;

$\}$

e$.$ Create a function and name it as CalAvg and the function accepts two integer arguments and

return one double. The function accepts integer array$1$ and the size of the array$1.$ And the

function returns the average of the entered values.

f$.$ Use your ID number digits as values stored in a two dimensional array. Write a C$++$ program

to:

a$.$ Display the two dimensional array in $3$ columns and $3$ rows. i$.$e$.$ if your id is $342169510,$ the

two dim array will be:

$342$

$169$

$510$

b$.$ Display the two dimensional array in $3$ columns and $3$ rows multiplied by itself. i$.$e$.$ if your

id is $34210956.$ The resulted output will be:

$9164$

$13681$

$2510$