Molarity HCl = .353 mol/L Trial 1 Sample 1 2 3 4 5 Temp at Decantation 60
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Molarity HCl = .353 mol/L
Trial 1 | |||||
Sample | 1 | 2 | 3 | 4 | 5 |
Temp at Decantation | 60 | 50 | 40.2 | 30 | 21.2 |
Vol. HCl used to reach end | 16.50 | 15.8 | 14.5 | 7.4 | 2.88 |
Trial 2 | |||||
Temp at Decantation | 61 | 50 | 38.0 | n/s | 22.0 |
Vol HCl used to reach end | 16.50 | 12.99 | 14.3 | n/s | 2.66 |
Avg Temp | 60.50 | 50 | 39.10 | 30.00 | 21.60 |
Avg Vol | 16.50 | 14.40 | 14.4 | 7.4 | 2.77 |
Molarity Tetraborate anion |
Calculate the molarity of B4O5(OH)4^2- (tetraborate anion) for each column using the average volme of HCl at the equivalence point and the average molarity of HCl which is : .353 mol/L
Remember that 5.0 mL of the tetraborate solution was titrated.
B4O5(OH)4^2-(aq) + 2 H+(aq) + 3 H2O(l) --> 4 H3BO3(aq)
Also.. how do you calculate Ksp?
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