More is Less $($Part II$).$ The order list for a project is as follows: Task$($t$)$ Prereq. A$(3)-$ B$(2)-$ C$(2)-$ D$(2)-$ E$(4)$ D F$(4)$ D G$(4)$ D H$(4)$ D I$(9)$ A The time is in hours, and the priority list is A$,$ B$,$ C$,...,$ I. Imagine there are three crews available. $1($a$)$ Draw the graph for this project. Make sure your graph has a start and an end. $($b$)$ Show that the time to completion is $12$ hours. $($c$)$ Now assume that the time for each task is reduced by one $($so that A now takes $2$ hours, B takes $1$ hours, and so on$).$ Show that the time to completion is $13$ hours. $4.$ More is Less $($Part III$).($a$)$ Use the same information as question $3($a$),$ except you may assume that there are four crews available. Show that the time to completion is $15$ hours. $($b$)$ Use the same information as question $3($a$)$ and three crews, except you may assume that there are no prerequisites. Show that the time to completion is $16$ hours.