prove that d [r.(vxa)]=r-(vxa). dt d [r.(vxa)]=r-(vxa). dt

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prove that $\frac{d}{d t}[\mathbf{r} \cdot(\mathbf{v} \times \mathbf{a})]=\mathbf{r} \cdot(\mathbf{v} \times \dot{\mathbf{a}})$

Related Book For answer-question

Applied Statistics for Public and Nonprofit Administration

ISBN: 978-1285737232

9th edition

Authors: Kenneth J. Meier, Jeffrey L. Brudney, John Bohte

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Posted Date: Oct 17, 2020 11:36 PM

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prove that d [r.(vxa)]=r-(vxa). dt d [r.(vxa)]=r-(vxa). dt

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d [r.(vxa)]=r-(vxa). dt d [r.(vxa)]=r-(vxa). dt

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d dt r vx a vx a r v vxa r axa r da x... View the full answer

Applied Statistics for Public and Nonprofit Administration

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