Question: MYSQL code This project involves using various Database concepts to solve Human Resources use cases. This requires skills like Database concepts, SQL Queries, etc. In

MYSQL code
This project involves using various Database concepts to solve Human Resources use cases. This requires skills like Database concepts, SQL Queries, etc.
In this project, the MySQL database schema consists of the following tables:
regions : It contains data of different regions of departments.
countries : It contains data where departments are based.
locations : It contains location data of departments.
departments : It contains all different departments.
employees : It contains data of all the employees.
jobs : It contains data for minimum and maximum salaries with respect to jobs.
Exercise
List the department ID and name
You need to write a SQL Query in order to solve the following problem:
A query to get the department ID and name of all the departments where no employee is working.
The final output shall contain four columns. i.e "DEPARTMENT_ID", "DEPARTMENT_NAME" , "MANAGER_ID", "LOCATION_ID".
Constraints
Time Limit: 1 sec(s)
Important Notes
Please note that sample data has already been loaded in a dedicated database for you. It is not being shared by anyone else.
In order to run the SQL Commands, please directly use table names in the queries and exclude the database name. Refer to some sample queries below for better understanding(Assume there is a table `customer` with columns `id`and `name` already loaded in a database `user`):
Write a SQL query to find the id of the customer whose name is 'ABC'.
The query that you need to put in the SQL Editor below would be: SELECT id from customer where name = 'ABC'
Write a SQL query to find the id of the customer whose name starts with 'ABC'.
The query that you need to put in the SQL Editor below would be: SELECT id from customer where name LIKE 'ABC%'

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