Question: n M/M/1 queue has an average interarrival time of 10 minutes and an average service time of 4 minutes. (1) What is the average queue

n M/M/1 queue has an average interarrival time of 10 minutes and an average service time of 4 minutes.

(1) What is the average queue length? customers (two decimal places)

(2) What is the probability (between 0 and 1) that there are more than one customers (i.e. two or more) in the system? (three decimal places)

If the service time follows a normal distribution with mean 4 minutes and standard deviation 1 minute(s) (assume the arrival process remains the same),

(3) What is the average time a customer spent in the system (waiting plus service time)? minutes (three decimal places)

If the service time is a fixed (constant) 4 minutes while the arrival process remains unchanged,

(4) What is the average time a customer spent in the queue (waiting time)? minutes

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