Question: N ( n , d ) = i = 1 d i * n d - i + 1 - j = 1 d n

N(n,d)=i=1di*nd-i+1-j=1dnj
N(n,d)= # of extra nodes IDS has compared to BFS
given the same depth and # of child nodes.
d= the depth of both IDS and BFS
n=# of child nodes per parent node
N ( n , d ) = i = 1 d i * n d - i + 1 - j = 1 d n

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