Question: Need a clear and detailed answer. a) Prove that the language L = {(D)D is a DFA that accepts an even length string} is decidable.

Need a clear and detailed answer.

Need a clear and detailed answer. a) Prove that the language L

a) Prove that the language L = {(D)D is a DFA that accepts an even length string} is decidable. b) What is wrong with the following proof? Why? T="On input string (D): 1. Check whether D represents a valid DFA. 2. Run D on the even length strings one by one. If it accepts one of them accept. Oth- erwise, reject." T is a decider, therefore, L is decidable

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