Question: need a python regular expression pattern that matches an optional name and equal sign followed by an integer in a function. Python names start with

need a python regular expression pattern that matches an optional name and equal sign followed by an integer in a function. Python names start with an alphabetic or underscore character, and continue with( alphabetic, numeric, or underscore). Integers have an optional sign followed by some non-zero numbers. It allows no spaces in the text.

Matches have name and value in a dictionary.

m = re.match(the-pattern,'x=3) m.groupdict() will return {'name': 'x', 'value': '3'}.

some test cases

re.match(p4a,'_a_b_c_12_=12').groupdict()-->{'name': '_a_b_c_12_', 'value': '12'}

re.match(p4a,'x=-12345').groupdict()-->{'name': 'x', 'value': '-12345'}

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