1. Need a slope triangle along the line but not using the data already plotted. (0,12),(2,10), (4,18),(6,26),(8,34), (10,42),(12,50)
2. Need to find 2 separate points Point A (X1, Y1) & Point B (X2 & Y2). Along the line between points (0,2), & (12,50)
3. To Find differnce of Y and X of the New 2 Points Use the NEW 2 Set of Coordinates and Plug information into and Use Slope=X2?X1Y2?Y1?
4. The Solution from (Y2-Y1)/(X2-X1) Is used in Slope=RUNRISE?
5. Find 2 separate points along the line and it cannot be the coordinates that were plotted .
6. Need to use 2 NEW coordinates on the line connect the 2 points along the line then sketch a right triangle, going from the first point to the second point.
7. Count the rise and the run on the legs of the triangle.
8. Take the ratio of rise to run to find the slope, M=RUNRISE?
9. Label Rise and Run and count how many space vertically the Y-Axis
   • Plot the 2 Additional points that is on the line. 2 new points in additio to the data which is the plotted points that that made the line
   • these points are between the minimum and maximum. The minimum is (0, 2) & ( 12,50)
   • Use the slope formula to identify the rise and the run.
   • Starting at the the 1st point choosen count out the rise and run to mark the second point.
   • Connect the points with a line.

The Slope of a Line. is m=riserunm=rise/run .

• The rise measures the vertical change

&

• the run measures the horizontal change.

FIND THE SLOPE USING 2 POINTS FROM THE LINE BUT NOT FROM THE DATA TABLE " WHICH MEANS ALONG THE LINE"

PLUG DATA IN AND SOLVE SLOPE OF 2 NEW POINTS ON THE LINE WITH NEW COORDINATES ND FIND RISE AND RUN FOR SLOPE PICTURE #1 GRAPH OF LINE OF PLOTTED DATA COORDINATES

X-axis: Range from O to 12 Y-axis: Range from 10 to 50 We'll use intervals of 5 for both axes. Plot the data points : (0, 2), (2, 10), (4, 18), (6, 26), (8, 34), (10, 42), (12, 50). y 5 10 15 20 25 30 35 \f