Question: Need help answering questions 1-3 please. Vibrational Motion Data: Data Comparison Basic parameters Maximum amplitude 0.12 m - total time - 4.76 = 0.95 sec

Need help answering questions 1-3 please.

Need help answering questions 1-3 please. Vibrational Motion Data: Data Comparison Basic

Vibrational Motion Data: Data Comparison Basic parameters Maximum amplitude 0.12 m - total time - 4.76 = 0.95 sec Time (sec) Position (m) Velocity (m/s) Acceleration (m/ $2) Period = # vibrations 5 Counting frequency f = 1/T = 1/0.95 = 1.05 Hz 0.76 0.11 0.0 - 3.8 1.04 0.0 Natural frequency W= 2Tif = 2x 3.14 x 1.05= 6.4 rad/s - 0.68 0.0 1.32 - 0.11 O. C 3.8 Force Constant and Natural Frequency 1.6 0.0 0. 68 0.0 Force constant (from graph) 3.587 N/m Question and Conclusions Natural frequency W=J(k/m) = J(3.587/0.100 = 5.989...= 6 rad/sec 1) Compare the theoretical values of the period, counting frequency and Counting frequency f = W/21 = 6/2x3.14= 0.96 Hz natural frequency, to the values determined from the graphs of motion. Were they close to each other? Explain. Period T= If = '/0.96 = 1.04 sec Velocity Graph 2) Compare the mass determined from the force-acceleration graph to the Maximum velocity (from graph) 0.68 m/s measured value. Were they close to each other? Explain. Maximum velocity (by calculation) Vmax = AW = (0.12)(6.0) = 0.72 m/s Acceleration Graph Maximum acceleration (from graph) 3.8 m/s& 3) How would the graphs and calculated values be different if a 200- Maximum acceleration (by calculation) a max = Awa= (0.12)(6.0)2= 4.32 m/sa gram mass was used instead of a 100-gram mass? Be specific. Answers Force Graph such as 'twice as much' or 'one-third the value' are encouraged. Constant mass (from graph) 0. 109 Kg (cat

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