Question: need help in python language 6.16LAB : Leap year - functions A common year in the modern Gregorian Calendat consists of 365 days. In reality,

need help in python language  need help in python language 6.16LAB : Leap year - functions
A common year in the modern Gregorian Calendat consists of 365 days.

6.16LAB : Leap year - functions A common year in the modern Gregorian Calendat consists of 365 days. In reality, Earth takes longer to rotate around the sun To account for the difterence in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29 th The, requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800 , etc.), the year must be evenly divisible by 400 ; therefore, both 1700 and 1800 are not leap years Some example leap years are 1600,1712 , and 2016 Write a program that takos in a year and determines the number of days in February for that year: Ex if the input is: 1712 the output is: Ex if the input is: 1913 Your program must define and call the following function. The funotion sihould refurn the number of days in February for the input ynar def days_in_feb(user_year)

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