Question: Need help plotting points on graph and solving a few parts. Each coffee table produced by Kevin Watson Designers nets the firm a profit of
Need help plotting points on graph and solving a few parts.

Each coffee table produced by Kevin Watson Designers nets the firm a profit of $10. Each bookcase yields a $6 profit. Watson's firm is small and its resources limited. During any given production period (of 1 week), 8 gallons of varnish and 14 lengths of high-quality redwood are available. Each coffee table requires approximately 1 gallon of varnish and 1 length of redwood. Each bookcase takes 1 gallon of varnish and 2 lengths of wood. The aim of the objective function for Kevin should be to the objective value. Decision variables: X= number of coffee tables produced / week Y= number of bookcases produced / week Objective function: Z=10X+6Y Subject to: 1X+1Y1X+2YX,Y0814(C1)(C2) On the graph on right, constraints C1 and C2 have been plotted. Using the point drawing tool, plot all the corner points for the feasible area. The optimum solution is: X= (round your response to two decimal places). Y= (round your response to two decimal places). Optimal solution value Z= (round your response to two decimal places). Each coffee table produced by Kevin Watson Designers nets the firm a profit of $10. Each bookcase yields a $6 profit. Watson's firm is small and its resources limited. During any given production period (of 1 week), 8 gallons of varnish and 14 lengths of high-quality redwood are available. Each coffee table requires approximately 1 gallon of varnish and 1 length of redwood. Each bookcase takes 1 gallon of varnish and 2 lengths of wood. The aim of the objective function for Kevin should be to the objective value. Decision variables: X= number of coffee tables produced / week Y= number of bookcases produced / week Objective function: Z=10X+6Y Subject to: 1X+1Y1X+2YX,Y0814(C1)(C2) On the graph on right, constraints C1 and C2 have been plotted. Using the point drawing tool, plot all the corner points for the feasible area. The optimum solution is: X= (round your response to two decimal places). Y= (round your response to two decimal places). Optimal solution value Z= (round your response to two decimal places)
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