Need help to fill out that table please

the pulley) gives: Application of Newton's 2nd law of rotational motion (7 = la , where ? is the total torque acted on 71 -t2 = T,r-T,r= la =12 or 71-12 =14 (4) The statement made just below Eq. (2) says that the tension T, = T, = T for an ideal Atwood's machine. In contrast, Eq. (4) shows that T, > T, for a real Atwood's machine, therefore, Eqs. (1) and (2) become: I = mg - ma and T2 = ma+ mg (5) Substitute (5) into (4) we have: mig - mg (6) my + m2 + * The pulley's moment of inertia has been measured using the Moment of inertia apparatus in Experiment 8.2, which has the value / =2x106 kg m?. The pulley's radius is r = 0.025 m. Optional exercises: If you have time, do the following calculations to see the effect of the pulley rotation. 1. Calculate do) (calc.) from Eq. (6) using the values of m, and m2 listed in Table 2 as well as the radius r and momentum of inertia I of the pulley (listed below Eq. (6)). Record the result in Table 2. 2. Calculate the percentage error between a(exp.) and do (calc.) . Record the error in Table 2. Table 2 Measurement Slope a(exp.) (6) (calc.) Percentage difference between Masses (kg) a(exp.) and a 6) (calc.) Measurement #1 m, = 0.060, m, = 0.050 Measurement #2 m, = 0.060, m, = 0.040 Measurement #3 m, = 0.055, m, = 0.045 Measurement #4 m, = 0.065, m, = 0.035