Need help with 20b and 21

For problems 19 - 21, use the following: At the end of a basketball game, a 6'5" basketball player threw a basketball vertically upward. The height of the basketball, h, in feet above ground after t seconds is given by: h(1) = -1612 + 401 + 6.5 (Round all answers to the nearest hundredth) (3) 19a . Find h (1.5) h (1.5) = 16 ( 1.5) + 40 ( 1.5 ) + 6.5 = (-16x 2.25 ) + 60 + 6.5 - 36+ 60 + 6. 5 h ( 1.5 ) = 30.5 (3) 19b . Explain the practical meaning of h(1.5 ) h= vertical height t = time take by basketball to reach at to vertical height is a function of time(t), means (n) depends on (t) , but it is independent. h (1.5 ) implies that for t = 1. 5 seconds, the max height attained by basketball is 30.5. ( 3 ) 20a . Determine the number of seconds it takes for the basketball to reach its maximum height. Show how you arrived at your answer. gh ( t ) = 0 (Round to hundredth) For the maximum height , dh (t ). dt at = 32+ 40 32 t + 210 = 0 410= 30t t= 40 32 - = 1. 25 secs the mac-height hit= 125)=-16 (1.25)"+ 40*1:25+ = -25+ 50+ 6..5 6.5 = 31.5 (3) 20b. Find the maximum height of the basketball. (4) 21. Write the equation you would solve to determine how long it would take for the basketball to hit the ground. DO NOT SOLVE THIS EQUATION