The joint and marginal pdf's of x = amount of almonds and Y =amount of cashews are

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f(x, y) fx(x) p= = 24xy 0 0 ≤ x ≤ 1,0 ≤ y ≤ 1, x + y ≤ 1 otherwise {12×(1- [12x(1x)² 0≤x≤ 1 otherwise with fy(y) obtained by replacing x by y in fx(x). It is easily verified that μx = μy = dy = ²/₁ Compute the correlation coefficient p for X and Y. Nin and E(XY) = ². Thus Cov(X, Y) = 2 75 f(x, y) fx(x) p= = 24xy 0 0 ≤ x ≤ 1,0 ≤ y ≤ 1, x + y ≤ 1 otherwise {12×(1- [12x(1x)² 0≤x≤ 1 otherwise with fy(y) obtained by replacing x by y in fx(x). It is easily verified that μx = μy = dy = ²/₁ Compute the correlation coefficient p for X and Y. Nin and E(XY) = ². Thus Cov(X, Y) = 2 75

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Similarly the expectation of the random variable Y is computed as ... View the full answer